9x^2+101x=-260

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Solution for 9x^2+101x=-260 equation:



9x^2+101x=-260
We move all terms to the left:
9x^2+101x-(-260)=0
We add all the numbers together, and all the variables
9x^2+101x+260=0
a = 9; b = 101; c = +260;
Δ = b2-4ac
Δ = 1012-4·9·260
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-29}{2*9}=\frac{-130}{18} =-7+2/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+29}{2*9}=\frac{-72}{18} =-4 $

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